It is impossible for digital to perfectly represent a sinewave.
A sinewave is a (sinusoidal shape) and a digital representation of sound consists of ones and zeros (or blocks) and therefore can never perfectly represent a sinusoidal wave. As resolution of the digital signal increases the closer it comes but will never achieve a true sinusoidal sinewave. Although, it can come close enough to achieve the illusion of a true analog sinewave.
It is impossible to create a curve by filling in squares on a sheet of graph paper but you can create the illusion of a curve.
Actually, Adam is right - he didn't express it brilliantly, but he is basically right.
Craig - I used to think like you. But it isn't right. Consider the following:
"if you sample at twice the highest frequency of interest, you will recover the waveform exactly, not approximately, not synthesised, but exactly, to the limits of the number of bits of quantisation. 2 samples at 20kHz will recover the 20kHz exactly. Don't forget that all music consists of sinewaves of varying amplitudes and frequencies, and in varying phase relationships, so as long as the system will record and reproduce those sinewaves accurately, then the system is transparent.
In the case of red-book, that provides for a dynamic range of 96dB and a bandwidth of 20kHz. That record companies prefer to restrict the dynamic range to 3dB less than bugger-all, has nothing to do with what the medium can support, and everything to do with what they think their customers want."
Got this from a UK forum thread, where I got told I was talking BS, and I was, I fully admit it. At some stage at school, I'm sure I did understand it - then my mind got warped by BS on the net... and other factors, like bad hi-fi mag articles.
Here is that thread if you want to understand digital processing - but you'll need some time...
What does sounding analogue mean?
Watch me get pulverised by Serge
![Big grin :D :D](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)